(MCQ from ETEA MDCAT 2023)
Q: Oxygen can be prepared by the decomposition of potassium chlorate (KClO₃). How many moles of oxygen (O₂) can be formed by taking 12 moles of potassium chlorate (KClO₃), according to the following equation?
2KClO₃ (s) + heat → 2KCl (s) + 3O₂ (g)
A) 12 moles of oxygen
B) 15 moles of oxygen
C) 18 moles of oxygen
D) 21 moles of oxygen
Correct Answer: C) 18 moles of oxygen
Explanation:
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